Algebra II question: A store owner bought a machine that laminates cards…?
Wednesday, June 30th, 2010 at
4:46 am
Question by ???: Algebra II question: A store owner bought a machine that laminates cards…?
The machine cost 00. Each laminated item costs the owner $.50, but he charges the customers .00 per item. How many cards must be laminated and sold before the owner makes a profit from the machine?
Best answer:
Answer by Ophiuchus
286 items
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Tagged with: Algebra • Bought • Cards • laminates • Machine • owner • question • store
Filed under: Pouch Laminator
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well, a profit would be greater than zero… the machine is 1000, and the profit on each card is 3.50.
So, here’s your formula:
-1000 + 3.50 x > 0
-1000 represents what he spent on the machine, 3.50 represents the profits he makes on the machine (charges 4.00 but has a cost of .50). That’s how much money he’s made.
Find the value of X, that’s how many cards that he needs to sell. You’ll need to round to the next largest whole number, since he can’t make .5 of a card or anything like that. Now do the rest of your homework yourself.